The vapour pressure of water at `80^(@)C` is 355 mm of Hg. 1 L vessel contains `O_(2)` at `80^(@)C`, which is saturated with water and the total pressure being 760 mm of Hg. The contents of the vessel were pumped into 0.3 L vessel at the same temperature. What is the partial presure of `O_(2)`?

Options

A. 1350 Hg
B. 2178.3 Hg
C. 121.5 Hg
D. 355 Hg

Answer

a

Explanation

(a) Volume of `O_(2)`=1 L
and `P_(O_(2))`=760-355=405 mm Hg
Since, the temperature is constant, using Boyle's law we get
`1 Lxx405 mm=0.3 LxxP'o_(2)
`:.` `P'o_(2) =1350 mmHg`