80 mL of `O_(2)` takes 2 minutes to pass through the hole. What volume of `SO_(2)` will pass through the hole in 3 minute?

Options

A. `(120)/(sqrt(2))` mL
B. `120xxsqrt(2)` mL
C. `(12)/(sqrt(2))` mL
D. None of these

Answer

a

Explanation

(a) `(r_(1))/(r_(2))=(V_(1)//t_(1))/(V_(2)//t_(2))=(V_(1)xxt_(2))/(V_(2)xxt_(1))=sqrt((M_(2))/(M_(1))),`
`(80xx3)/(V_(2)xx2)=sqrt((64)/(32))=sqrt(2), " " V_(2)=(120)/(sqrt(2))`