Under identical conditions of pressure and temperature, 4 L of gaseous moxture (`H_(2)` and `CH_(4)`) effuses through a hole in 5 min whereas 4 L of a gas X of molecular mass 36 takes to 10 min to effuse through the same hole. The mole ratio of `H_(2):CH_(4)` in the mixture is:

Options

A. `1:2`
B. `2:1`
C. `2:3`
D. `1:1`

Answer

d

Explanation

(d) `(r_("rmx"))/(r_(x))=(4//5)/(4//10)=2=sqrt((M_(x))/(M_("mix")))`
`impliesM_("mix")=9`
`M_("mix")=M_(H_(2))X_(H_(2))+M_(CH_(4))X_(CH_(4))`
`=2X_(H_(2))+16(1-X_(H_(2)))=9`
`implies" "X_(H_(2))=0.5`