If one mole of a mono-atomic gas `(gamma=5//3)` is mixed with one mole of a diatomic gas `(gamma=7//5)`, the value of `gamma` for the mixture is :

Options

A. 1.4
B. 1.428
C. 1.5
D. 1.33

Answer

c

Explanation

(c) `C_(v)=((3)/(2)R+(5)/(2)R)/(2)=2R`
`C_(p)=((5)/(2)R+(7)/(2)R)/(2)=3R`
`(C_(p))/(C_(v))=1.5`