If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture is

Options

A. 1.4
B. 1.5
C. 1.53
D. 3.07

Answer

b

Explanation

(b) `{:(C_(v)=(3)/(2)RT),(C_(p)=(5)/(2)RT):}` for monoatomic gas,
`{:(C_(v)=(5)/(2)2RT),(C_(p)=(7)/(2)RT):}` for diatomic gas
Thus, for mixture for 1 mole each,
`C_(v)=((3)/(2)RT+(5)/(2)RT)/(2)`
`and" "C_(p)=((5)/(2)RT+(7)/(2)RT)/(2)`
Thus, `(C_(p))/(C_(v))=(3RT)/(2RT)=1.5`