At low pressure, if `RT=2sqrt(a.P),` then the volume occupied by a real gas is :

Options

A. `(2RT)/(P)`
B. `(2P)/(RT)`
C. `(RT)/(2P)`
D. `(2RT)/(P)`

Answer

c

Explanation

(c) At low pressure,
`(P+(a)/(V^(2)))(V)=RT`
`i.e," "PV^(2)-RTV+a=0`
`V=(RT+-sqrt(R^(2)T^(2)-4Pa))/(2P)=(RT)/(2P)`
`( :' 4a.P=R^(2)T^(2))`