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At 273K temp, and 9 atm pressure, the co...

At `273K` temp, and 9 atm pressure, the compressibility fog a gas is `0.9`. The volume of 1 mill-moles of gas at this temperature and pressure is `:`

A

2.24 litre

B

0.020 mL

C

2.24 mL

D

22.4 mL

Text Solution

Verified by Experts

The correct Answer is:
c
(c) `Z=(PV)/(nRT)=(V)/(n)=(0.9xx0.0821xx273)/(9)`
`=2024"litre/mol"`
`:.` Volume of 1 milli-mole of gas =2.24 mL
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NARENDRA AWASTHI-GASEOUS STATE-Exercise
  1. The compressibility factor for a real gas at high pressure is .

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  2. The compressibillity of a gas is greater than unity at 1 atm and 273 K...

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  3. At 273K temp, and 9 atm pressure, the compressibility fog a gas is 0.9...

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  4. The compressibility factor for nitrogen at 330K and 800 atm is 1.90 an...

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  5. Consider the equation Z= (PV)/(RT). Which of the following statements ...

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  6. What is the compressibility factor (Z) for 0.02 mole of a van der Waal...

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  7. Consider the following statements If th van der Waals' parameters of t...

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  8. The van der Waals parameters for gases W, X, Y and Z are {:("Gas",a(...

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  9. Pressure remaining the constant, the volume of a given mass of an idea...

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  10. Define critical temperature.

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  11. The excluded volume of a gas will be larger, if (T(C))/(P(C)) is :

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  12. Select incorrect statement :

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  13. The correct order of temperature of a real gas is : (I) Boyle's temp...

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  14. The temperature at which the second virial coefficient of a real gas i...

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  15. The following organic compound are popularly known by their common nam...

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  16. van der Waal equation is true for :

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  17. However great the pressure , a gas cannot be liquified above its :

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  18. Inversion temperature (T(i)=(2a)/(Rb)) is defined as the temperature...

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  19. The van der Waals' equation of law of corresponding states for 1 mole ...

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  20. Calculate the volume occupied by 16gram O(2) at 300K and 8.31 Mpa if (...

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