The compressibility factor for nitrogen at `330K` and `800 atm` is `1.90` and at `570K` and `200 atm` is `1.10`. A certain mass of `N_(2)` occupies a volume of `1dm^(3)` at `330K` and `800 atm` calculate volume occupied by same quantity of `N_(2)` gas at `570 K` and `200 atm`

Options

A. 1 L
B. 2 L
C. 3 L
D. 4 L

Answer

d

Explanation

(d) `Z=(PV)/(nRT),1.90=(1xx800)/(nxxRxx330),`
`n=(1xx800)/(1.90xxRxx330)`
`Z=1.10=(Vxx200)/(nxxRxx570),`
`1.10=(Vxx200xx1.90xxRxx330)/(800xxRxx570)`
`V=4 L`