What is the compressibility factor (Z) for 0.02 mole of a van der Waals's gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible.
Given : RT=20 L atm `mol^(-1)` and a=1000 atm `L^(2) mol^(-2)`

Options

A. 2
B. 1
C. 0.02
D. 0.5

Answer

d

Explanation

(d) `(0.1+(1000xx(0.02)^(2))/(V^(2)))V=20xx0.02`
`=0.1V^(2)-0.4V+0.4=0`
`=V^(2)-4V+4=0`
`implies" "V=2L`
`Z=(PV)/(nRT)=(0.1xx2)/(20xx0.02)=0.5`