Two vessels connected by a valve of negligible volume. One container (I) has 2.8 g of `N_(2)` at temperature `T_(1) (K)`. The other container (II) is completely evacuated. The container (I) is heated to `T_(2)(K)`while container (II) is maintained at `T_(2)//3(K)`. volume of vessel (I) is half that of vessel (II). If the valve is opened then what is the mass ratio of `N_(2)` is both vessel `(W_(I)//W_(II))`?

Options

A. `1:2`
B. `1:3`
C. `1:6`
D. `3:1`

Answer

c

Explanation

(c)
Let x mole of `N_(2)` present into vessel II and P is final pressure of `N_(2)`
`P(2V)=xR(T_(2)//3)and P(V)=(0.1-x)RT_(2)`
`implies " "2=(x)/(3(0.1-x))`
`implies" "x=0.6//7"moles",`
`(0.6)/(7)xx28implies2.4 g N_(2)`
II has 2.4 g `N_(2)` and I has 0.4 g of `N_(2),`
`(W_(I))/(W_(II))=(0.4)/(2.4)implies1:6`