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The van der Waals' constantes for a gas ...

The van der Waals' constantes for a gas are `a=3.6 atmL^(2)mol^(-2),b=0.6Lmol^(-1)` .If `R=0.08LatmK^(-1)mol^(-1)` and the Boyle's temperature (K) is `T_(B)` of this gas, then what is the value of `(T_(B))/(15)`?

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The correct Answer is:
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`T_(B)=(a)/(Rb)=(3.6)/(0.08xx0.6)=75K,(75)/(15)=5K`
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