A substance, on analysis, gave the following percent composition: Na = 43.4%, C = 11.3 % and O = 45.3 %. Calculate the empirical formula. (At. mass Na = 23 u, C = 12 u, O = 16 u).

An organic compound on analysis gave the following results : C=54.5% ,O= 36.4 % H=9.1 % . The empirical formula of the compound is ____.

A compound on analysis gave the following percentage composition by mass: H = 9.09, O = 36.36, C = 54.55. Molecular mass of compound is 88. Find its molecular formula.

An organic compound on analysis gave C=39.9 % ,H= 6.7 % and O =53.4 % .The empricial formula of the compound is

Aspirin contains 60% C, 4.48% H and 35.5% O. Its empirical formula is

The chemical analysis of a compound having molecular mass gave =188, C 12.8%, H = 2.1 % and Br = 85.1%. Its molecular formula is

Find the formula mass of CaSO_4 , if the atomic mass of Ca = 40.1 u, S = 32.1 and O = 16.0 u

Calculate the mass percentage composition of the elements in nitric acid (H=1 ,N=14, O=16) .

An organic compound contains carbon hydrogen and oxygen. It elemental analysis gave C, 38.71% and H, 9.67% and O, 51.62%. The empirical formula of the compound would be __________.

Find the percentage composition constituents green vitriol crystals (FeSO_4*7H_2O) . Also find out the mass of iron and the water of crystallisaion in iron and the water of crystallisation in 4.54 kg of the crystals. (At. mass : Fe = 56, S = 32, O = 16 )