A compound on analysis gave the following percentage composition by mass: H = 9.09, O = 36.36, C = 54.55. Molecular mass of compound is 88. Find its molecular formula.

An organic compound on analysis gave the following results : C=54.5% ,O= 36.4 % H=9.1 % . The empirical formula of the compound is ____.

A substance, on analysis, gave the following percent composition: Na = 43.4%, C = 11.3 % and O = 45.3 %. Calculate the empirical formula. (At. mass Na = 23 u, C = 12 u, O = 16 u).

An organic compounds contains C= 21.56%, H= 4.56% and Br= 73.36 %. Its molecular mass is 109. Its molecular formula is

Answer the following questions in one word : Molecular formula of propane is C_3H_8 . From the Molecular formula draw its structural formula.

An organic compound containing oxygen, carbon, hydrogen and nitrogen contains 20 % carbon, 6.7 % hydrogen and 46.67 % nitrogen. Its molecular mass was found to be 60. Find the molecular formula of the compound.

0.30g of an organic compound containing C, H , and O an combustion yields 0.44g of CO_(2) and 0.18g of H_(2) O . If its molecular mass is 60 mu the molecular formula will be

An organic compound on analysis gave C=39.9 % ,H= 6.7 % and O =53.4 % .The empricial formula of the compound is

The chemical analysis of a compound having molecular mass gave =188, C 12.8%, H = 2.1 % and Br = 85.1%. Its molecular formula is