The ejection of the photoelectron from the silver metal in the photoelectric effect experiment can be stopped by applying the voltage of 0.35V when the radiation 256.7 nm is used. Calculate the work function for silver metal.

The velocity of the most energetic electrons emitted from a metallic surface is doubled when the frequency nu of incident radiation is double. The work function of this metal is

Photoelectric effect is described as the ejection of electrons from the surface of a metal when:

By stopping potential of 2 V, photoelectric current in photocell reduces to zero when cathode is exposed to light of wavelength 4000overset@ A . Calculate the work function of cathode surface..

When light of wavelength 6000oerset@A falls on a metal surface, photoelectrons are emitted from it with a velocity of 2 xx 10^5ms-1 .Calculate the work function of the metal in eV.

Consider a metal exposed to light of wavelength 600 nm. The maximum energy of the electron doubles when light of wavelength 400 nm is used. Find the work function in eV.

Photocurrent recorded in the micro ammeter in an experimental set-up of photoelectric effect vanishes when the retarding potential is more than 0.8 V if the wavelength of incident radiation is 4950overset@ A . If the source of incident radiation is changed, the stopping potential turns out to be 1.2 V. Find the work function of the cathode material and the wavelength of the second source.

Photocurrent recorded in the micro ammeter in an experimental set-up of photoelectric effect vanishes when the retarding potential is more than 0.8 V if the wavelength of incident radiation is 4950 overset (@)(A) . If the source of incident radiation is changed, the stopping potential turns out to be 1.2 V. Find the work function of the cathode material and the wavelength of the second source .