For the following equilibrium,`K_C=6.3 xx10 ^(14) at 1000 K ` `NO(g) + O_3(g) hArr NO_2(g)` +`O_2(g)` .Both the forward and reverse reactions in the equilibrium are elementray biomolecular reactions.What is, `K_c` . for the reverse reaction?

Justify the following reactions are redox rections : 4NH_3(g) + 5O_2(g) rarr 4NO(g) + 6H_2O (g)

The elementary reaction O_3(g) + O(g) rarr 2 O_2(g) is

A mixture of 1.57 mol of n_2 ,1.92 mol of H_2 and 8.13 mol of NH_3 is introduced into a 20 L reaction vessel at 500 kAt this temperature,the equilibrium constant. K_C for the reaction N_2(g) + 3H_2(g) hArr 2NH_3(g) is 1.7 xx 10 ^2 .Is the reaction mixture at equilibrium?If not,what is the direction of the net reaction?

For the reaction O_(3(g)) +O_((g)) to 2O_(2(g)) , if the rate law expression is , rate =k [O_3][O] the molecularity and order of the reaction are respectively ______.

For the following reaction at 298 K, H_(2(g))+1/2 O_(2(g))to H_2 O_((l)) , Which of the following alternative is CORRECT?