According to Bohr theory, which of the following transition in hydrogen atom will give rise to the least energetic proton?

Options

A. n = 6 to n = 5
B. n = 5 to n = 3
C. n = 6 to n = 1
D. n = 5 to n = 4

Answer

A

Explanation

`n^(2)=6, n_(1)=5" as "E prop [(1)/(n_(1)^(2))-(1)/(n_(2)^(2))]`
When `n_(2)^(2) gt n_(1)^(2)`, hydrogen will give rise to least energised photon.