A photon in X region is more energetic than in the visible region , X is :

Options

A. IR
B. UV
C. Microwave
D. Radio wave

Explanation

To solve the question, "A photon in X region is more energetic than in the visible region, X is:", we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Electromagnetic Spectrum**: The electromagnetic spectrum is divided into several regions based on the wavelength and energy of the photons. The order of energy from highest to lowest is as follows:
- Gamma Rays
- X-Rays
- Ultraviolet (UV) Rays
- Visible Light
- Infrared (IR) Rays
- Microwaves
- Radio Waves

2. **Identify the Visible Region**: The visible region of the electromagnetic spectrum is the range of wavelengths that can be detected by the human eye. It lies between the ultraviolet (UV) region and the infrared (IR) region.

3. **Determine Regions More Energetic than Visible**: Since the question states that the photon in region X is more energetic than in the visible region, we need to identify which regions have higher energy than visible light. The regions that have higher energy than visible light are:
- Ultraviolet (UV) Rays
- X-Rays
- Gamma Rays

4. **Check Given Options**: The question implies that we need to select from given options. If options include UV, X-Rays, or Gamma Rays, we would select the one that is more energetic than visible light.

5. **Conclusion**: Since the question states that X is more energetic than the visible region and if we assume that the options provided do not include X-Rays or Gamma Rays, the only possible answer left is the Ultraviolet (UV) region. Therefore, X corresponds to the UV region.

### Final Answer:
The answer is **Ultraviolet (UV) region**.

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