The shotest wave length in H spectrum of Lymen series when `R_(H)`=`109678cm^(-1)` is.

Options

A. 1002.7 Å
B. 1215.67 Å
C. 1127.30 Å
D. 911.7 Å

Answer

D

Explanation

For Lyman series `n_(1)=1`
For shortest .`l`. or Lyman series the energy different two levels showing transition should be maximum
`(i.e.n_(2)=oo)(1)/(lambda)=R_(H)[(1)/(1^(2))-(1)/(oo^(2))]`
`(1)/(lambda)=109678=lambda=911.7xx10^(-8)=911.7`Å