Equal volumes of two gases which do not react together are enclosed in separate vessel. Their pressure at 100 mm and 400 mm respectively. If the two vessel are joined together, then what will be the pressure of the resulting mixture (temperature remaining constant)?

Options

A. 125 mm
B. 500 mm
C. 1000 mm
D. 250 mm

Answer

D

Explanation

After joining vessel
Total number of moles `= n_1 + n_2 = (100 V)/(RT) + (400 V)/(RT)`
`therefore` Applying `PV = nRT `
`P = (nRT)/(V)`
Volume become double
`P = (((100 V)/(RT) + (400 V)/(RT))RT)/(2V) = (500 V)/(2V) = 250 mm`