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Equal weights of two gases of molecular ...

Equal weights of two gases of molecular weight 4 and 40 are mixed. The pressure of the mixture is 1.1 atm. The partial pressure of the light gas in this mixture is

A

0.55 atm

B

0.11 atm

C

1 atm

D

0.25 atm

Text Solution

Verified by Experts

The correct Answer is:
C
`"Partial pressure"_("Light gas") = (x/4)/(x/4 + x/40) xx 1.1`
`P.P_("Light gas") = 1 atm`
(Here x = wt. of each gas).
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