One mole of oxygen at 273 K and one mole of sulphur dioxide at 546 K are taken in two separate containers, then

Options

A. kinetic energy of `O_2 gt` kinetic energy of `SO_2`
B. kinetic energy `O_2 lt` kinetic energy of `SO_2`
C. kinetic energy of both are equal
D. none of the above

Answer

B

Explanation

`because KE = 3/2 RT`
`because KE prop T`
or `(KE_(O_2))/(KE_(SO_2)) = (T_(O_2))/(T_(SO_2)) = (273)/(546) = 1/2`
`KE_(SO_2) = 2KE_(O_2) `
`therefore KE_(SO_2) gt KE_(O_2)`