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If 4g of oxygen diffuses through a very ...

If 4g of oxygen diffuses through a very narrow hole, how much hydrogen would have diffused under identical conditions?

A

16g

B

1g

C

1/4 g

D

64 g

Text Solution

Verified by Experts

The correct Answer is:
B
`((dn//dt)_(O_2))/(dn//dt)_(H_2) = sqrt((M_(H_2))/(M_(O_2)))`
Here , x = wt of `H_2`
`((4//32)/(dt))/((x//2)/(dt)) = sqrt((2)/(32))`
`implies 8/(32 x) = 1/4`
`x = 1 g`
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