The average kinetic energy of an ideal gas per molecule in SI units at `25^(@)C` will be

Options

A. `6.17 xx 10^(-21) kJ`
B. `6.17 xx 10^(-21) J`
C. `6.17 xx 10^(-20) J`
D. `7.16 xx 10^(-20) J`

Answer

B

Explanation

`bar(K.E.) = 3/2 kT = 3/2 xx (8.314)/(6.02 xx 10^(23)) xx 298`
`= =6.17 xx 10^(-23) J`