The electrode pptenticals for
` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) `
and ` Cu^+ (aq) + e^- rarr Cu (s)`
are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.

Options

A. 0.150 V
B. 0.500 V
C. 0.325 V
D. 0.50 V

Answer

C

Explanation

`Cu^(2+) + e^(-) to Cu^(+), G_(1) =-n 0.15 F`
`Cu^(2+) + e^(-) to Cu, G_(2) = -n xx 0.50 F`
`Cu^(2+) +2e^(-) to Cu, G_(3)` = ?
`DeltaG_(3) = DeltaG_(1) + DeltaG_(2)`
`-2FE^(@) = -1F xx 0.15 xx (-1 F xx 0.5)`
`E^(@) = 0.65/2 = 0.325 V`