For the reduction of silver ions with copper metal, the standard cell potential was foound to be `+0.46 V` at `25^(@) C`. The value of standard Gibbs energy, `DeltaG^(@)` will be `(F = 96,500C mol^(-1))`:

Options

A. `-98.0 kJ`
B. `-89.0 kJ`
C. `-89.0 J`
D. `-44.5 kJ`

Answer

B

Explanation

`DeltaG^(@) = -nE^(@)F`
n=2 `Cu + 2Ag^(2+) to Cu^(2+) + 2Ag`
`=-2 xx 96500 xx 0.46`
`=-89 kJ`