The ionization constant of a weak electrolyte is `25 xx 10^(-6)` while the equivalent conductance of its 0.01 M solution is 19.6 s `cm^(2) eq^(-1)`. The equivalent conductance of the electrolyte at infinite dilution (in S `cm^(2)eq^(-1)`) will be

Options

A. 250
B. 196
C. 392
D. 384

Answer

C

Explanation

`K_(a) = 25 xx 10^(-6) = 19.6 S cm^(2) eq^(-1),l C=0.01`
`K_(a) =0.01 xx a^(2) rArr a = sqrt((25 xx 10^(-4))/10^(-2)) = 5 xx 10^(-2)`
`a = 5 xx 10^(-2) = 19.6/wedge_(aq)^(@) rArr wedge_(m)^(@) = 19.6/(5 xx 10^(-2))= 392`