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Given that wedge(m)^(@) = 133.45 cm^(2) ...

Given that `wedge_(m)^(@) = 133.45 cm^(2) mol^(-1) (AgNO_(3))` `wedge_(m)^(@) = 149.9 5 cm^(2) mol^(-1)` (KCl), `wedge_(m)^(@) = 144.0`
`(KNO_(3))` the molar conductivity at infinite diltue

A

`132 S cm^(2)"mol"^(-1)`

B

`140 S cm^(2) mol^(-1)`

C

`138 S cm^(2) mol^(-1)`

D

`134 S cm^(2) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`wedge_(m)^(+)(AgCl) = wedge_(m)^(@) (AgNO_(3)) + wedge_(m)^(@)(KCl) - wedge_(m)^(@)(KNO_(3))`
`=(133.4 + 149 - 144.9) S cm^(2)`
`=138.4 S cm^(2)`
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