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The rate constant k(1) and k(2) for two ...

The rate constant `k_(1)` and `k_(2)` for two different reactions are `10^(16) e^(-2000//T)` and `10^(15) e^(-1000//T)`, respectively. The temperature at which `k_(1) = k_(2)` is

A

1000 K

B

`(2000)/( 2.303) K`

C

`2000 K`

D

`(1000)/( 2.3030) K`

Text Solution

Verified by Experts

The correct Answer is:
D
`10^(16) e^(-2000//T) = 10^(15) e^(- 1000//T)`
`10 = e^(1000 T)`
`T = (1000)/ (2.303)`
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