The normality of 30 volume `H_(2)O_(2)` solution is `:`

Options

A. 3.57
B. 7.53
C. 5.36
D. 5.73

Answer

C

Explanation

30 vol = `3.035xx3=9.105%H_(2)O_(2)`
100 ml sol contain 9.105 gm `H_(2)O_(2)`
Hence 1000 ml solution contain 91.05 gm `H_(2)O_(2)`
Strength of `H_(2)O_(2)` = 91.05 gms/lit., basicity of `H_(2)O_(2)` = 2
Equivalent wt of `H_(2)O_(2)=(34/2)=17`
Normality = `("Strength")/("Eq. wt.")=91.05/17=5.3558`