`C_(5)H_(12)O` is a monohydri alcohol. How many isomers of this alcohol are possible? How many of these contain chiral centres as well as can exhibit enantiomerism?

Options

A. 7 and 2
B. 6 and 2
C. 4 and 2
D. 12 and 4

Explanation

To solve the question regarding the isomers of the monohydric alcohol with the molecular formula \( C_5H_{12}O \), we will follow these steps:

### Step 1: Determine the possible structural isomers of \( C_5H_{12}O \).

1. **Identify the basic structure**: The formula indicates a monohydric alcohol, which means it contains one hydroxyl group (-OH).
2. **Construct the carbon skeleton**: The carbon skeleton can be either straight-chain or branched. For five carbon atoms, we can have:
- Straight-chain: Pentanol (1-pentanol)
- Branched-chain:
- 2-pentanol
- 3-pentanol
- 2-methyl-1-butanol
- 3-methyl-1-butanol
- 2-methyl-2-butanol
- 3-methyl-2-butanol
- 2,2-dimethyl-1-propanol
- 2,3-dimethyl-1-butanol

### Step 2: Count the total number of isomers.

After constructing the possible structures, we find that there are a total of **8 structural isomers** of \( C_5H_{12}O \).

### Step 3: Identify chiral centers in the isomers.

1. **Definition of chiral centers**: A chiral center is a carbon atom that is bonded to four different groups.
2. **Examine each isomer**:
- **1-pentanol**: No chiral center.
- **2-pentanol**: No chiral center.
- **3-pentanol**: No chiral center.
- **2-methyl-1-butanol**: No chiral center.
- **3-methyl-1-butanol**: No chiral center.
- **2-methyl-2-butanol**: This is a chiral center.
- **3-methyl-2-butanol**: This is a chiral center.
- **2,2-dimethyl-1-propanol**: This is a chiral center.

### Step 4: Count the isomers that contain chiral centers.

From the analysis, we find that **3 of the isomers** contain chiral centers and can exhibit enantiomerism.

### Final Answer:
- **Total isomers**: 8
- **Isomers with chiral centers**: 3