In the reaction, `C_(2)H_(5)OHunderset(ZnCl_(2))overset(HX)rarrBoverset("Na/ether")rarrC,C` is

Options

A. Butane
B. Ethane
C. Iso butane
D. 2 - methyl butane

Explanation

To solve the question step by step, we will analyze the given reaction involving ethanol (C2H5OH) and its transformation through the specified reagents.

### Step 1: Identify the starting material
The starting material is ethanol, which can be represented as:
\[ \text{C}_2\text{H}_5\text{OH} \]

### Step 2: Reaction with HX and ZnCl2
Ethanol reacts with HX (where X is a halogen) in the presence of zinc chloride (ZnCl2). This reaction is known as the Lucas test, which converts alcohols into alkyl halides through a substitution reaction. The hydroxyl group (-OH) in ethanol is replaced by a halogen atom (X).

The reaction can be represented as:
\[ \text{C}_2\text{H}_5\text{OH} + \text{HX} \xrightarrow{\text{ZnCl}_2} \text{C}_2\text{H}_5\text{X} + \text{H}_2\text{O} \]

Here, the product formed is ethyl halide:
\[ \text{C}_2\text{H}_5\text{X} \]

### Step 3: Reaction of ethyl halide with sodium in ether
The next step involves the reaction of the ethyl halide (C2H5X) with sodium (Na) in an ether solvent. This reaction is known as the Wurtz reaction, which is used to couple alkyl halides to form higher alkanes.

The reaction can be represented as:
\[ 2 \text{C}_2\text{H}_5\text{X} + 2 \text{Na} \xrightarrow{\text{ether}} \text{C}_4\text{H}_{10} + 2 \text{NaX} \]

### Step 4: Identify the final product
The final product formed from the Wurtz reaction of ethyl halide is butane (C4H10):
\[ \text{C}_4\text{H}_{10} \]

### Conclusion
Thus, the final product C is butane.

### Summary of the Steps:
1. Start with ethanol (C2H5OH).
2. React with HX and ZnCl2 to form ethyl halide (C2H5X).
3. React ethyl halide with sodium in ether to form butane (C4H10).

### Final Answer
C is butane (C4H10).