The separation energy of the electron present in the shell n = 3 is 1.51 eV. What is the energy in the first excited state -

Options

A. `-1.51eV`
B. `-3.4 eV`
C. `+1.51eV`
D. `+3.4eV`

Answer

B

Explanation

`E_(n)=(-13.6Z^(2))/(n^(2))`
`1.51=(-13.6Z^(2))/(9), E_(2)=(-13.6Z^(2))/(4)=(-1.51xx9)/(4)=-3.4eV`