Which of the following set a of quantum numbers is currect for an electron in 4f orbital?

Options

A. `n=4, l=3, m= +4, s= +1//2`
B. `n=4, l=4, m= -4, s= -1//2`
C. `n=4, l=3, m= +1, s= +1//2`
D. `n=3, l=2, m= -2, s = +1//2`

Answer

C

Explanation

For 4f orbital electrons, n=4
`l=3` (because) `m=+3, +2, +1, 0, -1, -2, -3, s = +1//2`.