The number of protons, neutrons and electrons in `""_(71)^(175)Lu` respectively, are:

Options

A. 104, 71 and 71
B. 71, 71 and 104
C. 175, 104 and 71
D. 71, 104 and 71

Answer

D

Explanation

`""_(71)^(175)Lu`
Z = atomic number
Z = No. of Protons = 71 = No. of Electrons
No. of Neutrons = Mass no. - No. of Protons
`=175-71`
`=104`