Consider the molecules `CH_(4),NH_(3)` and `H_(2)O` which of the given statement is false ?

Options

A. The H-C-H bond angle in `CH_4` is larger than the H-N-H bond angle in `NH_3`
B. The H-C-H bond angle in `CH_2` the H-C-H bond angle in `NH_3` and the `H-O-H` bond angle in `H_2O` are all greater than `90^@`
C. Then H-O-H bond angle in `H_2O` is lager than the H-C-H bond angle in `CH_4`
D. The H-O-H bond angle in `H_2O` is smaller than the H-N-H bond angle in `NH_3`

Answer

C

Explanation

`CH_4 - sp^3` hybridised, tetrahedral bond angle `109^@28.`

` NH, -sp^3` hybridised, bond angle - `107^@`
`H_2O-sp^3` bend shaped
bond angle `-104^@5.`

So , bond angle of `H_2O` is less than that `NH_3&CH_4`