Home
Class 12
CHEMISTRY
Calculate molar conductivity of 0.15 M s...

Calculate molar conductivity of 0.15 M solution of KCl at 298 K if its conductivity is 0.0152 S `cm^(-1)`

A

`124 Omega^(-) cm^(2)"mol"^(-1)`

B

`204 Omega^(-1) cm^(2)"mol"^(-1)`

C

`101 Omega^(-1)cm^(2)"mol"^(-1)`

D

`30 Omega^(-1) cm^(2)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`wedge_(m) = (k xx 1000)/M = (0.0152 xx 1000)/0.15 = 101 Omega^(-1) cm^(2) mol^(-1)`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    PHYSICS WALLAH|Exercise LEVEL-2|60 Videos

  • ELECTROCHEMISTRY

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |32 Videos

  • COORDINATION COMPOUNDS

    PHYSICS WALLAH|Exercise NEET PAST 5 YEARS QUESTIONS |8 Videos

  • ENVIRONMENTAL CHEMISTRY

    PHYSICS WALLAH|Exercise NEET Past 5 Years Questions |4 Videos

Similar Questions

Explore conceptually related problems

Molar conductivity of 0.15 M solution of KCI at 298 K, if its conductivity is 0.0152 S cm^(-1) will be

The conductivity of 0.20M solution of KCl at 298K is 0.0248 S cm^(-1) . Calculate its molar conductivity.

Electrolytic conductivity of 0.30 M solution of KCl at 298 K is 3.72xx10^(2) " S "cm^(-1) . Calculate its molar conductivity.

The conductivity of 0.35M solution of KCl at 300K is 0.0275 S cm^(-1) . Calculate molar conductivity

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm^(-1) . Calculate its molar conductivity.

The resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If R of the same cell when filled with 0.02 M KCl solution is 520 Omega , calculate the conductivity and molar conductivity of 0.02 M KCl solution. The conductivity of 0.1 M KCl solution is 1.29 S m^(-1) .

PHYSICS WALLAH-ELECTROCHEMISTRY-NEET PAST 5 YEARS QUESTIONS
  1. Calculate molar conductivity of 0.15 M solution of KCl at 298 K if its...

    Text Solution

    |

  2. On electrolysis of dilute sulphuric acid using platinum electrodes, th...

    Text Solution

    |

  3. The number of Faradays(F) required to produce 20g of calcuim from molt...

    Text Solution

    |

  4. Identify the reaction from having top position in EMF series according...

    Text Solution

    |

  5. In a typical fuel cell, the reactants(R) and product (P) are:

    Text Solution

    |

  6. For a cell involving one electron E(cell)^(0)=0.59V and 298K, the equi...

    Text Solution

    |

  7. For the cell reaction: 2Fe^(3+)(aq)+2l^(-)(aq)to2Fe^(2+)(aq)+l(2)(aq...

    Text Solution

    |

  8. Consider the change in oxidation state of Bromine corredponding to dif...

    Text Solution

    |

  9. The emf of a Daniell cell at 298 K is E(1) Zn|ZnSO(4)(0.01 M)||CuSO(...

    Text Solution

    |

  10. Given that wedge(m)^(@) = 133.45 cm^(2) mol^(-1) (AgNO(3)) wedge(m)^(@...

    Text Solution

    |

  11. The zinc/silver oxide cell is used in electric current reaction is as ...

    Text Solution

    |

  12. During the electrolysis of molten sodium chloride, the time required t...

    Text Solution

    |

  13. Zine can be coated on iron to produce galvanize3d iron but the reverse...

    Text Solution

    |

  14. The number of electrons delivered at the cathode during electrolysis b...

    Text Solution

    |

  15. If the E^(@) for a given reaction has a negative value, then which of ...

    Text Solution

    |

  16. The molar conductivity of a 0.5 mol dm^(-1) solution with electrolytic...

    Text Solution

    |

  17. The pressure of H(2) required to make the potential of H(2)-electrode ...

    Text Solution

    |

  18. On elctrolysis of dil sulphuric acid using Platinum (Pt) electrode the...

    Text Solution

    |

  19. The number of Faraday.s (F) required to produce 20 g of calcium from C...

    Text Solution

    |

  20. Identify the reaction from following having top position is EMF series...

    Text Solution

    |

  21. In a typical fuel cell, the reactants (R) and product (P) are:

    Text Solution

    |