The number of electron delivered at the cathode during electolysis by a current of 1 amphere in 60 seconds is: (charge on electron `=1.50 xx 10^(-19) C`)

Options

A. `3.75 xx 10^(23)`
B. `7.48 xx 10^(23)`
C. `6 xx 10^(23)`
D. `6 xx 10^(23)`

Explanation

To solve the problem of determining the number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds, we can follow these steps:

### Step 1: Understand the relationship between charge, current, and time.
The total charge (q) can be calculated using the formula:
\[ q = I \times t \]
where:
- \( I \) is the current in amperes (A)
- \( t \) is the time in seconds (s)

### Step 2: Substitute the given values into the formula.
Given:
- \( I = 1 \, \text{A} \)
- \( t = 60 \, \text{s} \)

Substituting these values:
\[ q = 1 \, \text{A} \times 60 \, \text{s} = 60 \, \text{C} \]

### Step 3: Calculate the number of electrons using the charge of an electron.
The charge of one electron (e) is given as:
\[ e = 1.50 \times 10^{-19} \, \text{C} \]

The number of electrons (n) can be calculated using the formula:
\[ n = \frac{q}{e} \]

### Step 4: Substitute the values into the formula for n.
Substituting the values we have:
\[ n = \frac{60 \, \text{C}}{1.50 \times 10^{-19} \, \text{C}} \]

### Step 5: Perform the calculation.
Calculating \( n \):
\[ n = \frac{60}{1.50 \times 10^{-19}} \]
\[ n = 40 \times 10^{19} \]

### Step 6: Write the answer in scientific notation.
To express \( n \) in scientific notation:
\[ n = 4.0 \times 10^{20} \]

### Final Answer:
The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is:
\[ n = 4.0 \times 10^{20} \, \text{electrons} \]

---