How much will be reduction potential of a hydrogen electrolyte change when its solution initially at pH =0 is neutralised to pH=7

Options

A. Increase by 0.059 V
B. Decrease by 0.059 V
C. Increase by 0.41 V
D. Decrease by 0.41 V

Answer

D

Explanation

For H-electrode, R.P = 0.059 = pH
`E = E^(@) + 0.059 xx (log 10^(-7))`
`E = E^(@) +(0.059 xx (-7))/1 rArr E^(@) - 0.413 V`