108 g fairly concentrate solution of `AgNO_(3)` is electrolysis using 0.1 F electricity. The weight or resulting solution is:

Options

A. 94 g
B. 11.6 g
C. 96.4 g
D. None

Answer

C

Explanation

At anode: `2H_(2)O(l) to 4H^(+)(aq) + O_(2)(g) + 4e^(-)`
At Cathode: `Ag^(+) (aq) + e^(-) to Ag(s)`
Eq. Of `O_(2)` revolved =Eq. Of Ag formed `rArr 0.1`
Total loss in wt. `(0.1 xx 32)/4 + 0.1 xx 108 rArr 0.8 + 10.8 rArr 11.6`
wt. Of final solutions `=108 -11.6 rArr 96.4 g`