On elctrolysis of dil sulphuric acid using Platinum (Pt) electrode the product obtained at anode will be:

Options

A. Oxygen gas
B. `H_(2)S` gas
C. `SO_(2)` gas
D. Hydrogen gas

Explanation

To determine the product obtained at the anode during the electrolysis of dilute sulfuric acid using a platinum electrode, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Electrodes**:
- In electrolysis, there are two electrodes: the anode and the cathode. The anode is where oxidation occurs, and the cathode is where reduction occurs.

2. **Dissociation of Dilute Sulfuric Acid**:
- Dilute sulfuric acid (H₂SO₄) dissociates in water to produce hydrogen ions (H⁺) and sulfate ions (SO₄²⁻):
\[ H_2SO_4 \rightarrow 2H^+ + SO_4^{2-} \]

3. **Dissociation of Water**:
- Water (H₂O) also dissociates into hydrogen ions (H⁺) and hydroxide ions (OH⁻):
\[ H_2O \rightarrow H^+ + OH^- \]

4. **Identify the Reactions at the Electrodes**:
- At the anode (oxidation occurs), hydroxide ions (OH⁻) are discharged. The reaction can be represented as:
\[ 4OH^- \rightarrow 2H_2O + O_2 + 4e^- \]
- This indicates that oxygen gas (O₂) is produced at the anode.

5. **Identify the Reaction at the Cathode**:
- At the cathode (reduction occurs), hydrogen ions (H⁺) gain electrons to form hydrogen gas (H₂):
\[ 2H^+ + 2e^- \rightarrow H_2 \]

6. **Conclusion**:
- Therefore, the product obtained at the anode during the electrolysis of dilute sulfuric acid using a platinum electrode is oxygen gas (O₂).

### Final Answer:
The product obtained at the anode will be **oxygen gas (O₂)**.

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