The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)

Options

A. `3.75 xx 10^(20)`
B. `7.48 xx 10^(23)`
C. `6 xx 10^(23)`
D. `6 xx 10^(20)`

Answer

A

Explanation

According to Faraday.s law
Q = ne
Q = it
ne = it
`n =(1 xx 60)/(1.6 xx 10^(-19)) = 3.75 xx 10^(20)` electrons.