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In a zero-order reaction for every 10^(@...

In a zero-order reaction for every `10^(@)` rise of temperature, the rate is doubled. If the temperature is increased from `10^(@)C` to `100^(@)C`, the rate of the reaction will become

A

128 times

B

256 times

C

512 times

D

64 times

Text Solution

Verified by Experts

The correct Answer is:
C
According to Arrhenius factor for every `10^(@)` C change in the temperature the rate of reaction get double. Mathematically
`10^(@) C to 100^(@) C`
`(r_n)/( r_r) = 2^((2n)/( 10) ) = 512` times
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