In the presence of catalyst, the activation energy of the reaction is lowered by 2 kcal at `27^(@)C`. The rate of reaction will increased by

Options

A. 20 times
B. 28 times
C. 14 times
D. Remain time

Answer

B

Explanation

Arrhenius equation is `k=Ae^(-"ExRT")`
In the presence `k. = Ae^(-"ExRT")`
On dividing eg (ii) by eq (i), we get
`(k.)/( k) = c^("Ea"//"Rt"^1)// "RT"`
`(k.)/( k) = e((2000)/( 3 xx 300) ) = e^(3.33)`
`because` on taking log both sides,
`Log"" (k.)/( k) = (3.33)/( 2.303)`
`(k.)/( k) =` antilog `1.446 = 27.92 =28`
we know that, rate (R) `alpha` K
`therefore (R^1)/( R) = (k^2)/( k) 28`
`therefore R^1 = 28`R