In the reaction `NH_(4)NO_(2)(aq.) rarr N_(2)(g) + 2H_(2)O(l)` the volume of `N_(2)` after `20` min and after a long time is `40 ml` and `70 ml` respectively, The value of rate constant is :

Options

A. `(1//20) "In" (7//4) "min"^(-1)`
B. `(2.303//1200) "log" (7//3) "sec"^(-1)`
C. `(1//20) log (7//3) "min"^(-1)`
D. `(2.303//20) log (11/7) "min"^(-1)`

Answer

B

Explanation

`NH_(4) NO_(2) ("aq") to N_(2) (g) + 2H_(2) O(l)`
`k = (2.303)/( t) log((V_n -V_O)/(V_n -V_t)) rArr V_0 = 0`
`rArr k = (2.303)/( 20 ) log ((70 -0)/( 70 - 40))`
`= (2.303)/( 20 ) log ((70)/(30)) rArr k = (2.303)/( 1200) log"" (7)/(3)`