For the chemical reaction
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`
The correct option is:

Options

A. `- (1)/(3) (d [H_2])/( dt) = - (1)/(2) (d [NH_3])/(dt)`
B. `- (d[N_2])/(dt) = 2 (d [ NH_3])/(dt)`
C. `- (d[N_2])/(dt) = (1)/(2) (d[NH_3])/(dt)`
D. `3 (d[H_2])/(dt) = 2 (d[NH_2])/(dt)`

Answer

C

Explanation

`N_(2) + 3H_(2) hArr 2NH_(3)`
Rate of reaction is given as
`- (d [N_2])/( dt) = (1)/(3) (d[H_2])/( dt) = + (1)/( 2) (d [NH_3])/(dt)`