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The decomposition of phosphine [PH(3)] o...

The decomposition of phosphine `[PH_(3)]` on tungsten at low pressure is a first-order reaction. It is because the

A

Rate is proportional to the surface coverage

B

Rate is inversely proportional to the surface coverage

C

Rate is independent of the surface coverage

D

Rate of decomposition is very low

Text Solution

Verified by Experts

The correct Answer is:
A
At Low P, rate is proportional to the surface coverage and is of `1^(st)` order while at high P, it follows zero order due to complete coverage of surface area.
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