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The volume of oxygen evolved at STP by d...

The volume of oxygen evolved at STP by decomposition of `0.68g` '20 volume ' hydrogen peroxide solution is

A

2.24 ml

B

22.4 ml

C

224 ml

D

240 ml

Text Solution

Verified by Experts

The correct Answer is:
C
`underset(=2xx34=68g)underset("2 mol")(2H_(2)O_(2))tounderset(22400ml)underset("1 mole")(2H_(2)O+O_(2))`
`therefore` At STP, 68 g `H_(2)O_(2)` produced `O_(2)` = 22400 ml
`therefore` At STP, 0.68 g `H_(2)O_(2)` will produce
`O_(2)=(22400xx0.68)/60=224mL`
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