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H(3)C-C-=CH overset(H(2)O,H(4)SO(4))unde...

`H_(3)C-C-=CH overset(H_(2)O,H_(4)SO_(4))underset(HgSO_(4))to underset(A)("intermediate") to underset(B)("product")`

A

`A:H_(3) C- underset(SO_(4)) underset(|) (C)=CH_(2) B: H_(3)C- underset(O) underset(||)(C)-CH_(3)`

B

`A:H_(3) C- underset(OH) underset(|) (C)=CH_(2) B: H_(3)C- underset(O) underset(||)(C)-CH_(3)`

C

`A:H_(3) C- underset(OH) underset(|)(C)=CH_(2) B: H_(3)C- underset(SO_(4)) underset(||)(C)-CH_(2)`

D

`A:H_(3) C- underset(O) underset(|) (C)=CH_(2) B: H_(3)C-C-=H`

Text Solution

Verified by Experts

The correct Answer is:
B
`H_(3)SO_(4)`= Provided acidic medium.
`HgSO_(4)`= Act as a solvent
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