If `75%` of a first order reaction was completed in `90` minutes, `60%` of the same reaction would be completed in approximately ( in minutes)... (Take `:log2=0.3;log2.5=0.40`)

If 75% of a first order reaction was completed in 90 minutes, 60% of the same reaction would be completed in approximately (in minutes ) .............. (Take : log 2 = 0.30 , log 2.5 = 0.40)

75% of a first order reaction is completed in 32 minutes. 50% of the reaction would have been completed in

If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately (log 4 = 0.60 log 5 = 0.69)

If 75% of first order reaction is completed in 32 min, then 50% of the reaction would be complete in:

75% of a first order reaction was completed in 32 min. When was 50% of the reaction completed ?

If 60 % of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately [log = 4 = 0.60, log 5 = 0.69].

75% of a first-order reaction was completed in 32 minutes, when was 50% of the reaction completed ?