Home
Class 14
MATHS
From a solid cylinder whose height is 2....

From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest `cm^2` .

A

15 cm^2

B

18 cm^2

C

19 cm^2

D

13 cm^2

Text Solution

AI Generated Solution

The correct Answer is:
To find the total surface area of the remaining solid after hollowing out a conical cavity from a solid cylinder, we will follow these steps: ### Step 1: Determine the dimensions of the cylinder and cone - **Height of the cylinder (H)** = 2.4 cm - **Diameter of the cylinder** = 1.4 cm, hence **Radius (R)** = Diameter/2 = 1.4 cm / 2 = 0.7 cm ### Step 2: Calculate the curved surface area (CSA) of the cylinder The formula for the curved surface area of a cylinder is: \[ \text{CSA of Cylinder} = 2 \pi R H \] Substituting the values: \[ \text{CSA of Cylinder} = 2 \times \frac{22}{7} \times 0.7 \times 2.4 \] Calculating: \[ = 2 \times \frac{22}{7} \times 0.7 \times 2.4 = 10.56 \, \text{cm}^2 \] ### Step 3: Calculate the area of the base of the cylinder The area of the base of the cylinder is given by: \[ \text{Area of Base} = \pi R^2 \] Substituting the values: \[ \text{Area of Base} = \frac{22}{7} \times (0.7)^2 \] Calculating: \[ = \frac{22}{7} \times 0.49 = 1.54 \, \text{cm}^2 \] ### Step 4: Calculate the slant height (L) of the cone Using the Pythagorean theorem, the slant height \(L\) of the cone can be calculated as: \[ L = \sqrt{H^2 + R^2} \] Substituting the values: \[ L = \sqrt{(2.4)^2 + (0.7)^2} = \sqrt{5.76 + 0.49} = \sqrt{6.25} = 2.5 \, \text{cm} \] ### Step 5: Calculate the curved surface area (CSA) of the cone The formula for the curved surface area of the cone is: \[ \text{CSA of Cone} = \pi R L \] Substituting the values: \[ \text{CSA of Cone} = \frac{22}{7} \times 0.7 \times 2.5 \] Calculating: \[ = \frac{22}{7} \times 0.7 \times 2.5 = 5.5 \, \text{cm}^2 \] ### Step 6: Calculate the total surface area of the remaining solid The total surface area of the remaining solid is given by: \[ \text{Total Surface Area} = \text{CSA of Cylinder} + \text{Area of Base} + \text{CSA of Cone} \] Substituting the values: \[ \text{Total Surface Area} = 10.56 + 1.54 + 5.5 \] Calculating: \[ = 17.6 \, \text{cm}^2 \] ### Step 7: Round off the total surface area Rounding off to the nearest cm²: \[ \text{Total Surface Area} \approx 18 \, \text{cm}^2 \] ### Final Answer The total surface area of the remaining solid is approximately **18 cm²**.
Promotional Banner

Topper's Solved these Questions

  • SIMPLIFICATION

    RS AGGARWAL|Exercise question|15 Videos
  • SIMPLE INTEREST

    RS AGGARWAL|Exercise All Questions|124 Videos
  • SQUARE ROOTS AND CUBE ROOTS

    RS AGGARWAL|Exercise All Questions|219 Videos

Similar Questions

Explore conceptually related problems

From a solid cylinder whose height is 2.4cm and diameter 1.4cm, a conical cavity of the same height and same diameter is hollowed out.Find the total surface area of the remaining solid to the nearest cm^(2)

From a solid cylinder whose height is 15 cm and diameter 16 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid. [Use pi = 3.14.]

From a solid cylinder of height 2.8 cm and diameter 4.2 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid. (Take pi=22//7 )

From a solid cylinder whose height is 12 cm and diameter 10 cm , a conical cavity with the same base and height is taken out . Find the total surface area of the ramaining solid .

From a solid cylinder of height 36 cm and radius 14 cm a conical cavity of radus 7 cm and height 24 cm is drilled out . Find the volume and the total surface area of the remaining solid.

From a solid cylinder of height 24 cm and radius 7 cm , a conical cavity of the same height and same radius is taken out . Find the volume of remaining solid .

From a solid cylinder of height 4cm and radius 3cm a conical cavity of height 4cm of base radius 3cm is hollowed out. What is the total surface area of the remaining solid?

From a solid cylinder whose height is 8 cm and radius 6cm , a conical cavity of height 8 cm and of base radius 6 cm is hollowed out . Find the volume of the remaining solid.Also find the total surface area of the reamining solid.[ Take pi = 3.14 ]